Coil inductance thiab cua-core coil inductance formula

Oct 18, 2019|

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Coil inductance thiab cua-core coil inductance formula

Coil formula

Impedance (Ω)=2 * 3.14159 * F (ua haujlwm zaus) * Inductance (H), qhov teeb tsa yuav tsum muaj 360Ω impedance, yog li:

Inductance (H)=impedance (Ω) ÷ (2 * 3.14159) ÷ F (ua haujlwm zaus)=360 ÷ (2 * 3.14159) ÷ 7.06=8.116H

Raws li qhov no, tus naj npawb ntawm windings tuaj yeem suav tau:

Tus lej tig=[inductance * {(18 * lub voj voog txoj kab uas hla (吋)) + (40 * lub voj voog ntev (吋))}] ÷ lub voj voog txoj kab uas hla (吋)

Tus lej hloov pauv=[8.116 * {(18*2.047) + (40*3.74)}] ÷ 2.047=19 laps

Hollow inductance xam cov mis

Hollow inductance xam mis: L(mH){{0}}(0.08DDNN)/(3D+9W+10H)

D-coil txoj kab uas hla

N - tus naj npawb ntawm lem

d - txoj kab uas hla

H-coil qhov siab

W — coil dav

Cov units yog mm thiab mH feem.

Cua core inductance xam mis:

l=(0.01*D*N*N)/(L/D+0.44)

Coil inductance: l, chav tsev: Wei Heng

Txoj kab uas hla: D, unit: cm

Coil tig: N, unit: 匝

Coil ntev: L, unit: cm


Tug: Inductor qauv
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