Coil inductance thiab cua-core coil inductance formula
Oct 18, 2019| Nyob ruaj ntseg nrog SChitec
Coil inductance thiab cua-core coil inductance formula
Coil formula
Impedance (Ω)=2 * 3.14159 * F (ua haujlwm zaus) * Inductance (H), qhov teeb tsa yuav tsum muaj 360Ω impedance, yog li:
Inductance (H)=impedance (Ω) ÷ (2 * 3.14159) ÷ F (ua haujlwm zaus)=360 ÷ (2 * 3.14159) ÷ 7.06=8.116H
Raws li qhov no, tus naj npawb ntawm windings tuaj yeem suav tau:
Tus lej tig=[inductance * {(18 * lub voj voog txoj kab uas hla (吋)) + (40 * lub voj voog ntev (吋))}] ÷ lub voj voog txoj kab uas hla (吋)
Tus lej hloov pauv=[8.116 * {(18*2.047) + (40*3.74)}] ÷ 2.047=19 laps
Hollow inductance xam cov mis
Hollow inductance xam mis: L(mH){{0}}(0.08DDNN)/(3D+9W+10H)
D-coil txoj kab uas hla
N - tus naj npawb ntawm lem
d - txoj kab uas hla
H-coil qhov siab
W — coil dav
Cov units yog mm thiab mH feem.
Cua core inductance xam mis:
l=(0.01*D*N*N)/(L/D+0.44)
Coil inductance: l, chav tsev: Wei Heng
Txoj kab uas hla: D, unit: cm
Coil tig: N, unit: 匝
Coil ntev: L, unit: cm


